<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>POJ</title><link>https://blog.shuaizhang.cc/zh-hans/tags/poj/</link><description>查看归入当前术语的文章。</description><generator>Hugo</generator><language>zh-Hans</language><lastBuildDate>Tue, 13 Aug 2013 00:00:00 +0000</lastBuildDate><atom:link href="https://blog.shuaizhang.cc/zh-hans/tags/poj/index.xml" rel="self" type="application/rss+xml"/><item><title>Solution to POJ 1061</title><link>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1061/</link><pubDate>Tue, 13 Aug 2013 00:00:00 +0000</pubDate><guid>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1061/</guid><description>将问题转换为二元线性丢番图方程，然后运用扩展欧几里德算法求解。</description></item><item><title>Solution to POJ 1009</title><link>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1009/</link><pubDate>Mon, 01 Jul 2013 00:00:00 +0000</pubDate><guid>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1009/</guid><description>关键在于一定不能使用模拟法，并且要对几种情况进行有效的优化。</description></item><item><title>Solution to POJ 1018</title><link>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1018/</link><pubDate>Wed, 26 Jun 2013 00:00:00 +0000</pubDate><guid>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1018/</guid><description>Enumerate candidate bandwidths, compute the minimum total price for each one, and then maximize the final bandwidth-to-price ratio.</description></item><item><title>Solution to POJ 1019</title><link>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1019/</link><pubDate>Wed, 26 Jun 2013 00:00:00 +0000</pubDate><guid>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1019/</guid><description>Precompute the lengths of nested digit sequences, use binary search to locate the target block, and then extract the exact digit.</description></item><item><title>Solution to POJ 1045</title><link>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1045/</link><pubDate>Wed, 26 Jun 2013 00:00:00 +0000</pubDate><guid>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1045/</guid><description>Simplify the circuit equations, derive the closed-form relationship for the receiver voltage, and note the numeric-differentiation alternative.</description></item><item><title>POJ 1001 解题分析</title><link>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1001/</link><pubDate>Sat, 10 Jul 2010 00:00:00 +0000</pubDate><guid>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1001/</guid><description>这道题做了很多很多天，实在是非常不爽。一向最恶心高精度计算的题了，等有空了就写套类库出来，以后碰见就用 =w=</description></item><item><title>POJ 1002 解题分析</title><link>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1002/</link><pubDate>Mon, 05 Jul 2010 00:00:00 +0000</pubDate><guid>https://blog.shuaizhang.cc/zh-hans/posts/solution-to-poj-1002/</guid><description>这道题使用排序来解决基本上一定会超时，使用二叉查找树来做就可以了</description></item></channel></rss>